{ "

{ " 예상하지 못했습니다.} Twitter XML 역 직렬화

---

OAuth를 통해 Twitter에서 XML을 가져옵니다.

http://twitter.com/account/verify_credentials.xml을 요청 하여 다음 XML을 반환합니다.

<?xml version="1.0" encoding="UTF-8"?>
<user>
  <id>16434938</id>
  <name>Lloyd Sparkes</name>
  <screen_name>lloydsparkes</screen_name>
  <location>Hockley, Essex, UK</location>
  <description>Student</description>
  <profile_image_url>http://a3.twimg.com/profile_images/351849613/twitterProfilePhoto_normal.jpg</profile_image_url>
  <url>http://www.lloydsparkes.co.uk</url>
  <protected>false</protected>
  <followers_count>115</followers_count>
  <profile_background_color>9fdaf4</profile_background_color>
  <profile_text_color>000000</profile_text_color>
  <profile_link_color>220f7b</profile_link_color>
  <profile_sidebar_fill_color>FFF7CC</profile_sidebar_fill_color>
  <profile_sidebar_border_color>F2E195</profile_sidebar_border_color>
  <friends_count>87</friends_count>
  <created_at>Wed Sep 24 14:26:09 +0000 2008</created_at>
  <favourites_count>0</favourites_count>
  <utc_offset>0</utc_offset>
  <time_zone>London</time_zone>
  <profile_background_image_url>http://s.twimg.com/a/1255366924/images/themes/theme12/bg.gif</profile_background_image_url>
  <profile_background_tile>false</profile_background_tile>
  <statuses_count>1965</statuses_count>
  <notifications>false</notifications>
  <geo_enabled>false</geo_enabled>
  <verified>false</verified>
  <following>false</following>
  <status>
    <created_at>Mon Oct 12 19:23:47 +0000 2009</created_at>
    <id>4815268670</id>
    <text>&#187; @alexmuller your kidding? it should all be &quot;black tie&quot; dress code</text>
    <source>&lt;a href=&quot;http://code.google.com/p/wittytwitter/&quot; rel=&quot;nofollow&quot;&gt;Witty&lt;/a&gt;</source>
    <truncated>false</truncated>
    <in_reply_to_status_id>4815131457</in_reply_to_status_id>
    <in_reply_to_user_id>8645442</in_reply_to_user_id>
    <favorited>false</favorited>
    <in_reply_to_screen_name>alexmuller</in_reply_to_screen_name>
    <geo/>
  </status>
</user>

다음 코드를 직렬화 해제에 사용하고 있습니다.

    public User VerifyCredentials()
    {
        string url = "http://twitter.com/account/verify_credentials.xml";
        string xml = _oauth.oAuthWebRequestAsString(oAuthTwitter.Method.GET, url, null);

        XmlSerializer xs = new XmlSerializer(typeof(User),"");

        MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(xml));

        return (User)xs.Deserialize(ms);
    }

그리고 나는 User수업에 대해 다음을 가지고 있습니다 .

 [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class User
{

    [XmlElement(ElementName = "id")]       
    public long Id { get; set; }

    [XmlElement(ElementName = "name")] 
    public string Name { get; set; }

    [XmlElement(ElementName = "screen_name")]       
    public string ScreenName { get; set; }

    [XmlElement(ElementName = "location")]       
    public string Location { get; set; }

    [XmlElement(ElementName = "description")]      
    public string Description { get; set; }

    [XmlElement(ElementName = "profile_image_url")]      
    public string ProfileImageUrl { get; set; }

    [XmlElement(ElementName = "url")]       
    public string Url { get; set; }

    [XmlElement(ElementName = "protected")]      
    public bool Protected { get; set; }

    [XmlElement(ElementName = "followers_count")]      
    public int FollowerCount { get; set; }

    [XmlElement(ElementName = "profile_background_color")]       
    public string ProfileBackgroundColor { get; set; }

    [XmlElement(ElementName = "profile_text_color")]       
    public string ProfileTextColor { get; set; }

    [XmlElement(ElementName = "profile_link_color")]       
    public string ProfileLinkColor { get; set; }

    [XmlElement(ElementName = "profile_sidebar_fill_color")]       
    public string ProfileSidebarFillColor { get; set; }

    [XmlElement(ElementName = "profile_sidebar_border_color")]      
    public string ProfileSidebarBorderColor { get; set; }

    [XmlElement(ElementName = "friends_count")]     
    public int FriendsCount { get; set; }

    [XmlElement(ElementName = "created_at")]     
    public string CreatedAt { get; set; }

    [XmlElement(ElementName = "favourties_count")]      
    public int FavouritesCount { get; set; }

    [XmlElement(ElementName = "utc_offset")]      
    public int UtcOffset { get; set; }

    [XmlElement(ElementName = "time_zone")]       
    public string Timezone { get; set; }

    [XmlElement(ElementName = "profile_background_image_url")]        
    public string ProfileBackgroundImageUrl { get; set; }

    [XmlElement(ElementName = "profile_background_tile")]        
    public bool ProfileBackgroundTile { get; set; }

    [XmlElement(ElementName = "statuese_count")]        
    public int StatusesCount { get; set; }

    [XmlElement(ElementName = "notifications")]       
    public string Notifications { get; set; }

    [XmlElement(ElementName = "geo_enabled")]       
    public bool GeoEnabled { get; set; }

    [XmlElement(ElementName = "Verified")]        
    public bool Verified { get; set; }

    [XmlElement(ElementName = "following")]
    public string Following { get; set; }

    [XmlElement(ElementName = "status", IsNullable=true)]
    public Status CurrentStatus { get; set; }

}

그러나 위의 XML을 deserialize하면 응용 프로그램에서 다음이 발생합니다.

• $ exception { "XML 문서 (2, 2)에 오류가 있습니다."} System.Exception {System.InvalidOperationException}

• InnerException { "<user xmlns = ''>이 (가) 예상되지 않았습니다."} System.Exception {System.InvalidOperationException}

Now I have searched around and the best solution I can find is to add blank namespaces to the serializer when you serialize the content, but i'm not serializing it so I can't.

I also have some code for receiving Statuses, which works fine.

So can someone explain to me why the error is happening? As well as a possible solution?

Thanks in advance.

---

Either decorate your root entity with the XmlRoot attribute which will be used at compile time.

[XmlRoot(Namespace = "www.contoso.com", ElementName = "MyGroupName", DataType = "string", IsNullable=true)]

Or specify the root attribute when de serializing at runtime.

XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "user";
// xRoot.Namespace = "http://www.cpandl.com";
xRoot.IsNullable = true;

XmlSerializer xs = new XmlSerializer(typeof(User),xRoot);

---

Even easier is just to add the following annotations to the top of your class:

[Serializable, XmlRoot("user")]
public partial class User
{
}

---

XmlSerializer xs = new XmlSerializer(typeof(User), new XmlRootAttribute("yourRootName")); 

---

The error message is so vague, for me I had this code:

var streamReader = new StreamReader(response.GetResponseStream());
var xmlSerializer = new XmlSerializer(typeof(aResponse));
theResponse = (bResponse) xmlSerializer.Deserialize(streamReader);

Notice xmlSerializer is instantiated with aResponse but on deserializing I casted it accidentally to bResonse.

---

As John Saunders says, check if the class/property names matches the capital casing of your XML. If this isn't the case, the problem will also occur.

---

The simplest and best solution is just to use XMLRoot attribute in your class, in which you wish to deserialize.

Like:

[XmlRoot(ElementName = "YourPreferableNameHere")]
public class MyClass{
...
}

Also, use the following Assembly :

using System.Xml.Serialization;

---

My problem was one of my elements had the xmlns attribute:

<?xml version="1.0" encoding="utf-8"?>
<RETS ReplyCode="0">
    <RETS-RESPONSE xmlns="blahblah">
        ...
    </RETS-RESPONSE>
</RETS>

No matter what I tried the xmlns attribute seemed to be breaking the serializer, so I removed any trace of xmlns="..." from the xml file:

<?xml version="1.0" encoding="utf-8"?>
<RETS ReplyCode="0">
    <RETS-RESPONSE>
        ...
    </RETS-RESPONSE>
</RETS>

and voila! Everything worked.

I now parse the xml file to remove this attribute before deserializing. Not sure why this works, maybe my case is different since the element containing the xmlns attribute is not the root element.

---

The only thing that worked in my case was by using david valentine code. Using Root Attr. in the Person class did not help.

I have this simple Xml:

<?xml version="1.0"?>
<personList>
 <Person>
  <FirstName>AAAA</FirstName>
  <LastName>BBB</LastName>
 </Person>
 <Person>
  <FirstName>CCC</FirstName>
  <LastName>DDD</LastName>
 </Person>
</personList>

C# class:

public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
}

De-Serialization C# code from a Main method:

XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "personList";
xRoot.IsNullable = true;
using (StreamReader reader = new StreamReader(xmlFilePath))
{
List<Person> result = (List<Person>)(new XmlSerializer(typeof(List<Person>), xRoot)).Deserialize(reader);
 int numOfPersons = result.Count;
}  

---

My issue was that the root element actually has a xmlns="abc123"

So had to make XmlRoot("elementname",NameSpace="abc123")

---

All above not worked for me, but this was: Check that the name of Root element of class is exactly like the one from XML case sensitive.

---

In my case, my xml had multiple namespaces and attributes. So I used this site to generate the objects - https://xmltocsharp.azurewebsites.net/

And used the below code to deserialize

 XmlDocument doc =  new XmlDocument();
        doc.Load("PathTo.xml");
        User obj;
        using (TextReader textReader = new StringReader(doc.OuterXml))
        {
            using (XmlTextReader reader = new XmlTextReader(textReader))
            {
                XmlSerializer serializer = new XmlSerializer(typeof(User));
                obj = (User)serializer.Deserialize(reader);
            }
        }

참고URL : https://stackoverflow.com/questions/1556874/user-xmlns-was-not-expected-deserializing-twitter-xml