어떤 깊이에서든 이름으로 요소에 대한 XDocument 쿼리

어떤 깊이에서든 이름으로 요소에 대한 XDocument 쿼리

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나는이 XDocument개체를. LINQ를 사용하여 특정 깊이의 특정 이름을 가진 요소를 쿼리하고 싶습니다. 을 사용할 때 Descendants("element_name")현재 수준의 직접적인 하위 요소 만 가져옵니다. 내가 찾고있는 것은 XPath의 "// element_name"과 같습니다. 방금 사용해야합니까 XPath, 아니면 LINQ 메소드를 사용하여 수행 할 수 있습니까? 감사.

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후손은 절대적으로 잘 작동해야합니다. 예를 들면 다음과 같습니다.

using System;
using System.Xml.Linq;

class Test
{
    static void Main()
    {
        string xml = @"
<root>
  <child id='1'/>
  <child id='2'>
    <grandchild id='3' />
    <grandchild id='4' />
  </child>
</root>";
        XDocument doc = XDocument.Parse(xml);

        foreach (XElement element in doc.Descendants("grandchild"))
        {
            Console.WriteLine(element);
        }
    }
}

결과 :

<grandchild id="3" />
<grandchild id="4" />

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네임 스페이스를 나타내는 예제 :

String TheDocumentContent =
@"
<TheNamespace:root xmlns:TheNamespace = 'http://www.w3.org/2001/XMLSchema' >
   <TheNamespace:GrandParent>
      <TheNamespace:Parent>
         <TheNamespace:Child theName = 'Fred'  />
         <TheNamespace:Child theName = 'Gabi'  />
         <TheNamespace:Child theName = 'George'/>
         <TheNamespace:Child theName = 'Grace' />
         <TheNamespace:Child theName = 'Sam'   />
      </TheNamespace:Parent>
   </TheNamespace:GrandParent>
</TheNamespace:root>
";

XDocument TheDocument = XDocument.Parse( TheDocumentContent );

//Example 1:
var TheElements1 =
from
    AnyElement
in
    TheDocument.Descendants( "{http://www.w3.org/2001/XMLSchema}Child" )
select
    AnyElement;

ResultsTxt.AppendText( TheElements1.Count().ToString() );

//Example 2:
var TheElements2 =
from
    AnyElement
in
    TheDocument.Descendants( "{http://www.w3.org/2001/XMLSchema}Child" )
where
    AnyElement.Attribute( "theName" ).Value.StartsWith( "G" )
select
    AnyElement;

foreach ( XElement CurrentElement in TheElements2 )
{
    ResultsTxt.AppendText( "\r\n" + CurrentElement.Attribute( "theName" ).Value );
}

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이 방법으로 할 수 있습니다 :

xml.Descendants().Where(p => p.Name.LocalName == "Name of the node to find")

여기서 xmlA는 XDocument.

이 속성 Name은 a LocalName및 a 가있는 객체를 반환합니다 Namespace. 따라서 Name.LocalName이름별로 비교 하려면 사용해야 합니다.

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Descendants will do exactly what you need, but be sure that you have included a namespace name together with element's name. If you omit it, you will probably get an empty list.

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There are two ways to accomplish this,

1. Linq-to-xml
2. XPath

The following are samples of using these approaches,

List<XElement> result = doc.Root.Element("emails").Elements("emailAddress").ToList();

If you use XPath, you need to do some manipulation with the IEnumerable:

IEnumerable<XElement> mails = ((IEnumerable)doc.XPathEvaluate("/emails/emailAddress")).Cast<XElement>();

Note that

var res = doc.XPathEvaluate("/emails/emailAddress");

results either a null pointer, or no results.

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I am using XPathSelectElements extension method which works in the same way to XmlDocument.SelectNodes method:

using System;
using System.Xml.Linq;
using System.Xml.XPath; // for XPathSelectElements

namespace testconsoleApp
{
    class Program
    {
        static void Main(string[] args)
        {
            XDocument xdoc = XDocument.Parse(
                @"<root>
                    <child>
                        <name>john</name>
                    </child>
                    <child>
                        <name>fred</name>
                    </child>
                    <child>
                        <name>mark</name>
                    </child>
                 </root>");

            foreach (var childElem in xdoc.XPathSelectElements("//child"))
            {
                string childName = childElem.Element("name").Value;
                Console.WriteLine(childName);
            }
        }
    }
}

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Following @Francisco Goldenstein answer, I wrote an extension method

using System.Collections.Generic;
using System.Linq;
using System.Xml.Linq;

namespace Mediatel.Framework
{
    public static class XDocumentHelper
    {
        public static IEnumerable<XElement> DescendantElements(this XDocument xDocument, string nodeName)
        {
            return xDocument.Descendants().Where(p => p.Name.LocalName == nodeName);
        }
    }
}

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we know the above is true. Jon is never wrong; real life wishes can go a little further

<ota:OTA_AirAvailRQ
    xmlns:ota="http://www.opentravel.org/OTA/2003/05" EchoToken="740" Target=" Test" TimeStamp="2012-07-19T14:42:55.198Z" Version="1.1">
    <ota:OriginDestinationInformation>
        <ota:DepartureDateTime>2012-07-20T00:00:00Z</ota:DepartureDateTime>
    </ota:OriginDestinationInformation>
</ota:OTA_AirAvailRQ>

For example, Usually the problem is, how can we get EchoToken in the above xml document? Or how to blur the element with the name attrbute.

1- You can find them by accessing with the namespace and the name like below

doc.Descendants().Where(p => p.Name.LocalName == "OTA_AirAvailRQ").Attributes("EchoToken").FirstOrDefault().Value

2- You can find it by the attribute content value, like this one

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This my variant of the solution based on Linq and Descendants method of the XDocument class

using System;
using System.Linq;
using System.Xml.Linq;

class Test
{
    static void Main()
    {
        XDocument xml = XDocument.Parse(@"
        <root>
          <child id='1'/>
          <child id='2'>
            <subChild id='3'>
                <extChild id='5' />
                <extChild id='6' />
            </subChild>
            <subChild id='4'>
                <extChild id='7' />
            </subChild>
          </child>
        </root>");

        xml.Descendants().Where(p => p.Name.LocalName == "extChild")
                         .ToList()
                         .ForEach(e => Console.WriteLine(e));

        Console.ReadLine();
    }
}

Results:

For more details on the Desendants method take a look here.

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(Code and Instructions is for C# and may need to be slightly altered for other languages)

This example works perfect if you want to read from a Parent Node that has many children, for example look at the following XML;

<?xml version="1.0" encoding="UTF-8"?> 
<emails>
    <emailAddress>jdoe@set.ca</emailAddress>
    <emailAddress>jsmith@hit.ca</emailAddress>
    <emailAddress>rgreen@set_ig.ca</emailAddress> 
</emails>

Now with this code below (keeping in mind that the XML File is stored in resources (See the links at end of snippet for help on resources) You can obtain each email address within the "emails" tag.

XDocument doc = XDocument.Parse(Properties.Resources.EmailAddresses);

var emailAddresses = (from emails in doc.Descendants("emailAddress")
                      select emails.Value);

foreach (var email in emailAddresses)
{
    //Comment out if using WPF or Windows Form project
    Console.WriteLine(email.ToString());

   //Remove comment if using WPF or Windows Form project
   //MessageBox.Show(email.ToString());
}

Results

1. jdoe@set.ca
2. jsmith@hit.ca
3. rgreen@set_ig.ca

Note: For Console Application and WPF or Windows Forms you must add the "using System.Xml.Linq;" Using directive at the top of your project, for Console you will also need to add a reference to this namespace before adding the Using directive. Also for Console there will be no Resource file by default under the "Properties folder" so you have to manually add the Resource file. The MSDN articles below, explain this in detail.

Adding and Editing Resources

How to: Add or Remove Resources

참고URL : https://stackoverflow.com/questions/566167/query-an-xdocument-for-elements-by-name-at-any-depth