Programing

Jquery 라디오 버튼이 선택된 경우

lottogame 2020. 6. 21. 19:40
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Jquery 라디오 버튼이 선택된 경우


중복 가능성 :
특정 라디오 버튼 확인이 확인되었습니다.

나는이 2 개의 라디오 버튼이있어 가격에 우송료가 필요한지 여부를 결정할 수 있습니다.

<input type="radio" id="postageyes" name="postage" value="Yes" /> Yes
<input type="radio" id="postageno" name="postage" value="No" /> No

Jquery를 사용하여 'yes'라디오 버튼이 선택되어 있는지 확인하고 그렇다면 '추가'기능을 수행해야합니다. 누군가 내가 어떻게 할 수 있는지 말해 줄 수 있습니까?

도움을 주셔서 감사합니다

편집하다:

내 코드를 이것으로 업데이트했지만 작동하지 않습니다. 내가 뭔가 잘못하고 있습니까?

<script type='text/javascript'>
// <![CDATA[
jQuery(document).ready(function(){

$('input:radio[name="postage"]').change(function(){
    if($(this).val() == 'Yes'){
       alert("test");
    }
});

});

// ]]>
</script>

$('input:radio[name="postage"]').change(
    function(){
        if ($(this).is(':checked') && $(this).val() == 'Yes') {
            // append goes here
        }
    });

또는 위의-다시-조금 불필요한 jQuery를 사용하십시오.

$('input:radio[name="postage"]').change(
    function(){
        if (this.checked && this.value == 'Yes') {
            // note that, as per comments, the 'changed'
            // <input> will *always* be checked, as the change
            // event only fires on checking an <input>, not
            // on un-checking it.
            // append goes here
        }
    });

수정 된 (개선 된) jQuery :

// defines a div element with the text "You're appendin'!"
// assigns that div to the variable 'appended'
var appended = $('<div />').text("You're appendin'!");

// assigns the 'id' of "appended" to the 'appended' element
appended.id = 'appended';

// 1. selects '<input type="radio" />' elements with the 'name' attribute of 'postage'
// 2. assigns the onChange/onchange event handler
$('input:radio[name="postage"]').change(
    function(){

        // checks that the clicked radio button is the one of value 'Yes'
        // the value of the element is the one that's checked (as noted by @shef in comments)
        if ($(this).val() == 'Yes') {

            // appends the 'appended' element to the 'body' tag
            $(appended).appendTo('body');
        }
        else {

            // if it's the 'No' button removes the 'appended' element.
            $(appended).remove();
        }
    });

var appended = $('<div />').text("You're appendin'!");
appended.id = 'appended';
$('input:radio[name="postage"]').change(function() {
  if ($(this).val() == 'Yes') {
    $(appended).appendTo('body');
  } else {
    $(appended).remove();
  }
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<input type="radio" id="postageyes" name="postage" value="Yes" />Yes
<input type="radio" id="postageno" name="postage" value="No" />No

JS 피들 데모 .

And, further, a mild update (since I was editing to include Snippets as well as the JS Fiddle links), in order to wrap the <input /> elements with <label>s - allow for clicking the text to update the relevant <input /> - and changing the means of creating the content to append:

var appended = $('<div />', {
  'id': 'appended',
  'text': 'Appended content'
});
$('input:radio[name="postage"]').change(function() {
  if ($(this).val() == 'Yes') {
    $(appended).appendTo('body');
  } else {
    $(appended).remove();
  }
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>
  <input type="radio" id="postageyes" name="postage" value="Yes" />Yes</label>
<label>
  <input type="radio" id="postageno" name="postage" value="No" />No</label>

JS Fiddle demo.

Also, if you only need to show content depending on which element is checked by the user, a slight update that will toggle visibility using an explicit show/hide:

// caching a reference to the dependant/conditional content:
var conditionalContent = $('#conditional'),
    // caching a reference to the group of inputs, since we're using that
    // same group twice:
    group = $('input[type=radio][name=postage]');

// binding the change event-handler:
group.change(function() {
  // toggling the visibility of the conditionalContent, which will
  // be shown if the assessment returns true and hidden otherwise:
  conditionalContent.toggle(group.filter(':checked').val() === 'Yes');
  // triggering the change event on the group, to appropriately show/hide
  // the conditionalContent on page-load/DOM-ready:
}).change();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>
  <input type="radio" id="postageyes" name="postage" value="Yes" />Yes</label>
<label>
  <input type="radio" id="postageno" name="postage" value="No" />No</label>
<div id="conditional">
  <p>This should only show when the 'Yes' radio &lt;input&gt; element is checked.</p>
</div>

And, finally, using just CSS:

/* setting the default of the conditionally-displayed content
to hidden: */
#conditional {
  display: none;
}

/* if the #postageyes element is checked then the general sibling of
that element, with the id of 'conditional', will be shown: */
#postageyes:checked ~ #conditional {
  display: block;
}
<!-- note that the <input> elements are now not wrapped in the <label> elements,
in order that the #conditional element is a (subsequent) sibling of the radio
<input> elements: -->
<input type="radio" id="postageyes" name="postage" value="Yes" />
<label for="postageyes">Yes</label>
<input type="radio" id="postageno" name="postage" value="No" />
<label for="postageno">No</label>
<div id="conditional">
  <p>This should only show when the 'Yes' radio &lt;input&gt; element is checked.</p>
</div>

JS Fiddle demo.

References:


Try this

if($("input:radio[name=postage]").is(":checked")){
  //Code to append goes here
}

Something like this:

if($('#postageyes').is(':checked')) {
// do stuff
}

$('input:radio[name="postage"]').change(function(){
    if($(this).val() === 'Yes'){
       // append stuff
    }
});

This will listen for a change event on the radio buttons. At the time the user clicks Yes, the event will fire and you will be able to append anything you like to the DOM.


if($('#test2').is(':checked')) {
    $(this).append('stuff');
} 

$("input").bind('click', function(e){
   if ($(this).val() == 'Yes') {
        $("body").append('whatever');
   }
});

Try this:

if ( jQuery('#postageyes').is(':checked') ){ ... }

jQuery('input[name="inputName"]:checked').val()

This will listen to the changed event. I have tried the answers from others but those did not work for me and finally, this one worked.

$('input:radio[name="postage"]').change(function(){
    if($(this).is(":checked")){
        alert("lksdahflk");
    }
});

참고URL : https://stackoverflow.com/questions/6654601/jquery-if-radio-button-is-checked

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