관리자에게 Django 앱에 자세한 이름을 지정할 수 있습니까?

관리자에게 Django 앱에 자세한 이름을 지정할 수 있습니까?

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Django 관리자에 나타나는 필드와 모델에 자세한 이름을 지정할 수있는 것과 같은 방법으로 앱에 사용자 지정 이름을 지정할 수 있습니까?

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장고 1.8+

당 1.8 문서 (그리고 현재 문서 )

새로운 응용 프로그램은 피해야 default_app_config합니다. 대신에 적절한 AppConfig서브 클래스에 대한 점으로 구분 된 경로를 명시 적으로 구성해야합니다 INSTALLED_APPS.

예:

INSTALLED_APPS = [
    # ...snip...
    'yourapp.apps.YourAppConfig',
]

그런 다음 AppConfig아래 나열된대로 변경하십시오 .

장고 1.7

rhunwicks의 OP에 대한 언급에서 알 수 있듯이, 이것은 장고 1.7 이후 즉시 가능합니다.

문서 에서 가져온 것 :

# in yourapp/apps.py
from django.apps import AppConfig

class YourAppConfig(AppConfig):
    name = 'yourapp'
    verbose_name = 'Fancy Title'

그런 다음 default_app_config변수를YourAppConfig

# in yourapp/__init__.py
default_app_config = 'yourapp.apps.YourAppConfig'

장고 1.7 이전

모델 정의에서 app_label을 정의하여 애플리케이션에 사용자 정의 이름을 지정할 수 있습니다. 그러나 django가 관리자 페이지를 작성함에 따라 app_label로 모델을 해시하므로 하나의 애플리케이션에 표시하려면 모든 애플리케이션 모델에서이 이름을 정의해야합니다.

class MyModel(models.Model):
        pass
    class Meta:
        app_label = 'My APP name'

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rhunwicks의 OP에 대한 언급에서 알 수 있듯이, 이것은 장고 1.7 이후 즉시 가능합니다.

문서 에서 가져온 것 :

# in yourapp/apps.py
from django.apps import AppConfig

class YourAppConfig(AppConfig):
    name = 'yourapp'
    verbose_name = 'Fancy Title'

그런 다음 default_app_config변수를YourAppConfig

# in yourapp/__init__.py
default_app_config = 'yourapp.apps.YourAppConfig'

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앱에 둘 이상의 모델이있는 경우 메타 정보가있는 모델을 만들고 모든 모델에 대해 해당 클래스의 하위 클래스를 만듭니다.

class MyAppModel(models.Model):
    class Meta:
        app_label = 'My App Label'
        abstract = True

class Category(MyAppModel):
     name = models.CharField(max_length=50)

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그들에게 verbose_name 속성을 제공하십시오.

희망을 가지지 마십시오. 또한 django.contrib.admin.sites의 색인보기를 자신의 ProjectAdminSite보기로 복사하여 사용자 정의 관리 인스턴스에 포함시켜야합니다.

class ProjectAdminSite(AdminSite):
    def index(self, request, extra_context=None):
        copied stuff here...

admin.site = ProjectAdminSite()

then tweak the copied view so that it uses your verbose_name property as the label for the app.

I did it by adding something a bit like this to the copied view:

        try:
            app_name = model_admin.verbose_name
        except AttributeError:
            app_name = app_label

While you are tweaking the index view why not add an 'order' property too.

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Well I started an app called todo and have now decided I want it to be named Tasks. The problem is that I already have data within my table so my work around was as follows. Placed into the models.py:

    class Meta:
       app_label = 'Tasks'
       db_table = 'mytodo_todo'

Hope it helps.

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For Django 1.4 (not yet released, but trunk is pretty stable), you can use the following method. It relies on the fact that AdminSite now returns a TemplateResponse, which you can alter before it is rendered.

Here, we do a small bit of monkey patching to insert our behaviour, which can be avoided if you use a custom AdminSite subclass.

from functools import wraps
def rename_app_list(func):
    m = {'Sites': 'Web sites',
         'Your_app_label': 'Nicer app label',
    }

    @wraps(func)
    def _wrapper(*args, **kwargs):
        response = func(*args, **kwargs)
        app_list = response.context_data.get('app_list')

        if app_list is not None:
            for a in app_list:
                name = a['name']
                a['name'] = m.get(name, name)
        title = response.context_data.get('title')
        if title is not None:
            app_label = title.split(' ')[0]
            if app_label in m:
                response.context_data['title'] = "%s administration" % m[app_label]
        return response
    return _wrapper

admin.site.__class__.index = rename_app_list(admin.site.__class__.index)
admin.site.__class__.app_index = rename_app_list(admin.site.__class__.app_index)

This fixes the index and the app_index views. It doesn't fix the bread crumbs in all other admin views.

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First you need to create a apps.py file like this on your appfolder:

# appName/apps.py

# -*- coding: utf-8 -*-             
from django.apps import AppConfig

class AppNameConfig(AppConfig):
    name = 'appName'
    verbose_name = "app Custom Name"

To load this AppConfig subclass by default:

# appName/__init__.py
default_app_config = 'appName.apps.AppNameConfig'

Is the best way to do. tested on Django 1.7

For the person who had problems with the Spanish

This code enable the utf-8 compatibility on python2 scripts

# -*- coding: utf-8 -*-

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No, but you can copy admin template and define app name there.

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I'm using django-admin-tools for that.

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There is a hack that can be done that does not require any migrations. Taken from Ionel's blog and credit goes to him: http://blog.ionelmc.ro/2011/06/24/custom-app-names-in-the-django-admin/

There is also a ticket for this that should be fixed in Django 1.7 https://code.djangoproject.com/ticket/3591

"""

Suppose you have a model like this:

class Stuff(models.Model):
    class Meta:
        verbose_name = u'The stuff'
        verbose_name_plural = u'The bunch of stuff'

You have verbose_name, however you want to customise app_label too for different display in admin. Unfortunatelly having some arbitrary string (with spaces) doesn't work and it's not for display anyway.

Turns out that the admin uses app_label. title () for display so we can make a little hack: str subclass with overriden title method:

class string_with_title(str):
    def __new__(cls, value, title):
        instance = str.__new__(cls, value)
        instance._title = title
        return instance

    def title(self):
        return self._title

    __copy__ = lambda self: self
    __deepcopy__ = lambda self, memodict: self

Now we can have the model like this:

class Stuff(models.Model):
    class Meta:
        app_label = string_with_title("stuffapp", "The stuff box")
        # 'stuffapp' is the name of the django app
        verbose_name = 'The stuff'
        verbose_name_plural = 'The bunch of stuff'

and the admin will show "The stuff box" as the app name.

"""

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If you already have existing tables using the old app name, and you don't want to migrate them, then just set the app_label on a proxy of the original model.

class MyOldModel(models.Model):
    pass

class MyNewModel(MyOldModel):
    class Meta:
        proxy = True
        app_label = 'New APP name'
        verbose_name = MyOldModel._meta.verbose_name

Then you just have to change this in your admin.py:

#admin.site.register(MyOldModel, MyOldModelAdmin)
admin.site.register(MyNewModel, MyOldModelAdmin)

Be aware that the url will be /admin/NewAPPname/mynewmodel/ so you might just want to make sure that the class name for the new model looks as close to the old model as possible.

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The following plug-and-play piece of code works perfectly since Django 1.7. All you have to do is copy the below code in the __init__.py file of the specific app and change the VERBOSE_APP_NAME parameter.

from os import path
from django.apps import AppConfig

VERBOSE_APP_NAME = "YOUR VERBOSE APP NAME HERE"


def get_current_app_name(file):
    return path.dirname(file).replace('\\', '/').split('/')[-1]


class AppVerboseNameConfig(AppConfig):
    name = get_current_app_name(__file__)
    verbose_name = VERBOSE_APP_NAME


default_app_config = get_current_app_name(__file__) + '.__init__.AppVerboseNameConfig'

If you use this for multiple apps, you should factor out the get_current_app_name function to a helper file.

참고URL : https://stackoverflow.com/questions/612372/can-you-give-a-django-app-a-verbose-name-for-use-throughout-the-admin