프로그래밍 방식으로 식별 열이있는 SQL 테이블을 확인하는 방법

프로그래밍 방식으로 식별 열이있는 SQL 테이블을 확인하는 방법

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T-SQL에 ID 열과 해당 테이블이있는 SQL Server 2005의 열 목록을 만들고 싶습니다.

결과는 다음과 같습니다.

TableName, ColumnName

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시스템 테이블 (버전에 따라 변경 될 수 있음)에 덜 의존하는 SQL Server에 대해이 작업을 수행하는 또 다른 잠재적 방법은 INFORMATION_SCHEMA 뷰를 사용하는 것입니다.

select COLUMN_NAME, TABLE_NAME
from INFORMATION_SCHEMA.COLUMNS
where COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
order by TABLE_NAME 

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sys.columns.is_identity = 1

예 :

select o.name, c.name
from sys.objects o inner join sys.columns c on o.object_id = c.object_id
where c.is_identity = 1

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다른 방법 (2000/2005/2012/2014) :

IF ((SELECT OBJECTPROPERTY( OBJECT_ID(N'table_name_here'), 'TableHasIdentity')) = 1)
    PRINT 'Yes'
ELSE
    PRINT 'No'

참고 : table_name_here해야 schema.table스키마가 아닌, dbo.

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SQL 2005에서 :

select object_name(object_id), name
from sys.columns
where is_identity = 1

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이 쿼리는 트릭을 수행하는 것 같습니다.

SELECT 
    sys.objects.name AS table_name, 
    sys.columns.name AS column_name
FROM sys.columns JOIN sys.objects 
    ON sys.columns.object_id=sys.objects.object_id
WHERE 
    sys.columns.is_identity=1
    AND
    sys.objects.type in (N'U')

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여기 MSSQL 2000의 작동 버전이 있습니다. 여기에있는 2005 코드를 수정했습니다. http://sqlfool.com/2011/01/identity-columns-are-you-nearing-the-limits/

/* Define how close we are to the value limit
   before we start throwing up the red flag.
   The higher the value, the closer to the limit. */
DECLARE @threshold DECIMAL(3,2);
SET @threshold = .85;

/* Create a temp table */
CREATE TABLE #identityStatus
(
      database_name     VARCHAR(128)
    , table_name        VARCHAR(128)
    , column_name       VARCHAR(128)
    , data_type         VARCHAR(128)
    , last_value        BIGINT
    , max_value         BIGINT
);

DECLARE @dbname sysname;
DECLARE @sql nvarchar(4000);

-- Use an cursor to iterate through the databases since in 2000 there's no sp_MSForEachDB command...

DECLARE c cursor FAST_FORWARD FOR
SELECT
    name
FROM
    master.dbo.sysdatabases 
WHERE 
    name NOT IN('master', 'model', 'msdb', 'tempdb');

OPEN c;

FETCH NEXT FROM c INTO @dbname;

WHILE @@FETCH_STATUS = 0
BEGIN
    SET @sql = N'Use [' + @dbname + '];
    Insert Into #identityStatus
    Select ''' + @dbname + ''' As [database_name]
        , Object_Name(id.id) As [table_name]
        , id.name As [column_name]
        , t.name As [data_type]
        , IDENT_CURRENT(Object_Name(id.id)) As [last_value]
        , Case 
            When t.name = ''tinyint''   Then 255 
            When t.name = ''smallint''  Then 32767 
            When t.name = ''int''       Then 2147483647 
            When t.name = ''bigint''    Then 9223372036854775807
          End As [max_value]
    From 
        syscolumns As id
        Join systypes As t On id.xtype = t.xtype
    Where 
        id.colstat&1 = 1    -- this identifies the identity columns (as far as I know)
    ';

    EXECUTE sp_executesql @sql;

    FETCH NEXT FROM c INTO @dbname;
END

CLOSE c;
DEALLOCATE c;

/* Retrieve our results and format it all prettily */
SELECT database_name
    , table_name
    , column_name
    , data_type
    , last_value
    , CASE 
        WHEN last_value < 0 THEN 100
        ELSE (1 - CAST(last_value AS FLOAT(4)) / max_value) * 100 
      END AS [percentLeft]
    , CASE 
        WHEN CAST(last_value AS FLOAT(4)) / max_value >= @threshold
            THEN 'warning: approaching max limit'
        ELSE 'okay'
        END AS [id_status]
FROM #identityStatus
ORDER BY percentLeft;

/* Clean up after ourselves */
DROP TABLE #identityStatus;

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List of tables without Identity column based on Guillermo answer:

SELECT DISTINCT TABLE_NAME
FROM            INFORMATION_SCHEMA.COLUMNS
WHERE        (TABLE_SCHEMA = 'dbo') AND (OBJECTPROPERTY(OBJECT_ID(TABLE_NAME), 'TableHasIdentity') = 0)
ORDER BY TABLE_NAME

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The following query work for me:

select  TABLE_NAME tabla,COLUMN_NAME columna
from    INFORMATION_SCHEMA.COLUMNS
where   COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
order by TABLE_NAME

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I think this works for SQL 2000:

SELECT 
    CASE WHEN C.autoval IS NOT NULL THEN
        'Identity'
    ELSE
        'Not Identity'
    AND
FROM
    sysobjects O
INNER JOIN
    syscolumns C
ON
    O.id = C.id
WHERE
    O.NAME = @TableName
AND
    C.NAME = @ColumnName

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This worked for me using Sql Server 2008:

USE <database_name>;
GO
SELECT SCHEMA_NAME(schema_id) AS schema_name
    , t.name AS table_name
    , c.name AS column_name
FROM sys.tables AS t
JOIN sys.identity_columns c ON t.object_id = c.object_id
ORDER BY schema_name, table_name;
GO

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Use this :

DECLARE @Table_Name VARCHAR(100) 
DECLARE @Column_Name VARCHAR(100)
SET @Table_Name = ''
SET @Column_Name = ''

SELECT  RowNumber = ROW_NUMBER() OVER ( PARTITION BY T.[Name] ORDER BY T.[Name], C.column_id ) ,
    SCHEMA_NAME(T.schema_id) AS SchemaName ,
    T.[Name] AS Table_Name ,
    C.[Name] AS Field_Name ,
    sysType.name ,
    C.max_length ,
    C.is_nullable ,
    C.is_identity ,
    C.scale ,
    C.precision
FROM    Sys.Tables AS T
    LEFT JOIN Sys.Columns AS C ON ( T.[Object_Id] = C.[Object_Id] )
    LEFT JOIN sys.types AS sysType ON ( C.user_type_id = sysType.user_type_id )
WHERE   ( Type = 'U' )
    AND ( C.Name LIKE '%' + @Column_Name + '%' )
    AND ( T.Name LIKE '%' + @Table_Name + '%' )
ORDER BY T.[Name] ,
    C.column_id

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This worked for SQL Server 2005, 2008, and 2012. I found that the sys.identity_columns did not contain all my tables with identity columns.

SELECT a.name AS TableName, b.name AS IdentityColumn
FROM sys.sysobjects a 
JOIN sys.syscolumns b 
ON a.id = b.id
WHERE is_identity = 1
ORDER BY name;

Looking at the documentation page the status column can also be utilized. Also you can add the four part identifier and it will work across different servers.

SELECT a.name AS TableName, b.name AS IdentityColumn
FROM [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.sysobjects a 
JOIN [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.syscolumns b 
ON a.id = b.id
WHERE is_identity = 1
ORDER BY name;

Source: https://msdn.microsoft.com/en-us/library/ms186816.aspx

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By some reason sql server save some identity columns in different tables, the code that work for me, is the following:

select      TABLE_NAME tabla,COLUMN_NAME columna
from        INFORMATION_SCHEMA.COLUMNS
where       COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1
union all
select      o.name tabla, c.name columna
from        sys.objects o 
inner join  sys.columns c on o.object_id = c.object_id
where       c.is_identity = 1

참고URL : https://stackoverflow.com/questions/87747/how-do-you-determine-what-sql-tables-have-an-identity-column-programmatically