아래 디렉토리를 파지 않고 os.walk

아래 디렉토리를 파지 않고 os.walk

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os.walk내가 제공 한 디렉토리의 파일 만 반환하도록 제한 하려면 어떻게합니까 ?

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        for f in files:
            if os.path.splitext(f)[1] in whitelist:
                outputList.append(os.path.join(root, f))
            else:
                self._email_to_("ignore")
    return outputList

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walklevel기능을 사용하십시오 .

import os

def walklevel(some_dir, level=1):
    some_dir = some_dir.rstrip(os.path.sep)
    assert os.path.isdir(some_dir)
    num_sep = some_dir.count(os.path.sep)
    for root, dirs, files in os.walk(some_dir):
        yield root, dirs, files
        num_sep_this = root.count(os.path.sep)
        if num_sep + level <= num_sep_this:
            del dirs[:]

처럼 작동 os.walk하지만 level재귀의 깊이를 나타내는 매개 변수를 전달할 수 있습니다 .

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os.walk를 사용하지 마십시오.

예:

import os

root = "C:\\"
for item in os.listdir(root):
    if os.path.isfile(os.path.join(root, item)):
        print item

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해결책은 실제로 매우 간단하다고 생각합니다.

사용하다

break

for 루프의 첫 번째 반복 만 수행하려면 더 우아한 방법이 있어야합니다.

for root, dirs, files in os.walk(dir_name):
    for f in files:
        ...
        ...
    break
...

os.walk를 처음 호출하면 현재 디렉토리에 대한 튤립을 반환 한 다음 다음 디렉토리의 내용을 루프합니다.

원본 스크립트를 가져 와서 휴식을 추가하십시오 .

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        for f in files:
            if os.path.splitext(f)[1] in whitelist:
                outputList.append(os.path.join(root, f))
            else:
                self._email_to_("ignore")
        break
    return outputList

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사용 제안 listdir은 좋은 것입니다. Python 2에서 귀하의 질문에 대한 직접적인 대답은 root, dirs, files = os.walk(dir_name).next().

동등한 Python 3 구문은 다음과 같습니다. root, dirs, files = next(os.walk(dir_name))

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You could use os.listdir() which returns a list of names (for both files and directories) in a given directory. If you need to distinguish between files and directories, call os.stat() on each name.

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If you have more complex requirements than just the top directory (eg ignore VCS dirs etc), you can also modify the list of directories to prevent os.walk recursing through them.

ie:

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        dirs[:] = [d for d in dirs if is_good(d)]
        for f in files:
            do_stuff()

Note - be careful to mutate the list, rather than just rebind it. Obviously os.walk doesn't know about the external rebinding.

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The same idea with listdir, but shorter:

[f for f in os.listdir(root_dir) if os.path.isfile(os.path.join(root_dir, f))]

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for path, dirs, files in os.walk('.'):
    print path, dirs, files
    del dirs[:] # go only one level deep

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Felt like throwing my 2 pence in.

baselevel = len(rootdir.split("\\"))
for subdirs, dirs, files in os.walk(rootdir):
    curlevel = len(subdirs.split("\\"))
    if curlevel <= baselevel + 1:
        [do stuff]

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In Python 3, I was able to do this:

import os
dir = "/path/to/files/"

#List all files immediately under this folder:
print ( next( os.walk(dir) )[2] )

#List all folders immediately under this folder:
print ( next( os.walk(dir) )[1] )

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You could also do the following:

for path, subdirs, files in os.walk(dir_name):
    for name in files:
        if path == ".": #this will filter the files in the current directory
             #code here

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Since Python 3.5 you can use os.scandir instead of os.listdir. Instead of strings you get an iterator of DirEntry objects in return. From the docs:

Using scandir() instead of listdir() can significantly increase the performance of code that also needs file type or file attribute information, because DirEntry objects expose this information if the operating system provides it when scanning a directory. All DirEntry methods may perform a system call, but is_dir() and is_file() usually only require a system call for symbolic links; DirEntry.stat() always requires a system call on Unix but only requires one for symbolic links on Windows.

You can access the name of the object via DirEntry.name which is then equivalent to the output of os.listdir

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This is how I solved it

if recursive:
    items = os.walk(target_directory)
else:
    items = [next(os.walk(target_directory))]

...

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There is a catch when using listdir. The os.path.isdir(identifier) must be an absolute path. To pick subdirectories you do:

for dirname in os.listdir(rootdir):
  if os.path.isdir(os.path.join(rootdir, dirname)):
     print("I got a subdirectory: %s" % dirname)

The alternative is to change to the directory to do the testing without the os.path.join().

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You can use this snippet

for root, dirs, files in os.walk(directory):
    if level > 0:
        # do some stuff
    else:
        break
    level-=1

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create a list of excludes, use fnmatch to skip the directory structure and do the process

excludes= ['a\*\b', 'c\d\e']
for root, directories, files in os.walk('Start_Folder'):
    if not any(fnmatch.fnmatch(nf_root, pattern) for pattern in excludes):
        for root, directories, files in os.walk(nf_root):
            ....
            do the process
            ....

same as for 'includes':

if **any**(fnmatch.fnmatch(nf_root, pattern) for pattern in **includes**):

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Why not simply use a range and os.walk combined with the zip? Is not the best solution, but would work too.

For example like this:

# your part before
for count, (root, dirs, files) in zip(range(0, 1), os.walk(dir_name)):
    # logic stuff
# your later part

Works for me on python 3.

Also: A break is simpler too btw. (Look at the answer from @Pieter)

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A slight change to Alex's answer, but using __next__():

print(next(os.walk('d:/'))[2]) or print(os.walk('d:/').__next__()[2])

with the [2] being the file in root, dirs, file mentioned in other answers

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root folder changes for every directory os.walk finds. I solver that checking if root == directory

def _dir_list(self, dir_name, whitelist):
    outputList = []
    for root, dirs, files in os.walk(dir_name):
        if root == dir_name: #This only meet parent folder
            for f in files:
                if os.path.splitext(f)[1] in whitelist:
                    outputList.append(os.path.join(root, f))
                else:
                    self._email_to_("ignore")
    return outputList

---

import os

def listFiles(self, dir_name):
    names = []
    for root, directory, files in os.walk(dir_name):
        if root == dir_name:
            for name in files:
                names.append(name)
    return names

참고URL : https://stackoverflow.com/questions/229186/os-walk-without-digging-into-directories-below