확장명이 여러 개인 GetFiles

확장명이 여러 개인 GetFiles [중복]

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중복 가능성 :
여러 필터를 사용하여 Directory.GetFiles ()를 호출 할 수 있습니까?

둘 이상의 확장을 어떻게 필터링합니까?

난 노력 했어:

FileInfo[] Files = dinfo.GetFiles("*.jpg;*.tiff;*.bmp");
FileInfo[] Files = dinfo.GetFiles("*.jpg,*.tiff,*.bmp");

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확장 방법을 생성하지 않는 이유는 무엇입니까? 더 읽기 쉽습니다.

public static IEnumerable<FileInfo> GetFilesByExtensions(this DirectoryInfo dir, params string[] extensions)
{
    if (extensions == null) 
         throw new ArgumentNullException("extensions");
    IEnumerable<FileInfo> files = Enumerable.Empty<FileInfo>();
    foreach(string ext in extensions)
    {
       files = files.Concat(dir.GetFiles(ext));
    }
    return files;
}

편집 : 더 효율적인 버전 :

public static IEnumerable<FileInfo> GetFilesByExtensions(this DirectoryInfo dir, params string[] extensions)
{
    if (extensions == null) 
         throw new ArgumentNullException("extensions");
    IEnumerable<FileInfo> files = dir.EnumerateFiles();
    return files.Where(f => extensions.Contains(f.Extension));
}

용법:

DirectoryInfo dInfo = new DirectoryInfo(@"c:\MyDir");
dInfo.GetFilesByExtensions(".jpg",".exe",".gif");

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모든 파일을 가져온 다음 배열을 필터링 할 수 있습니다.

public static IEnumerable<FileInfo> GetFilesByExtensions(this DirectoryInfo dirInfo, params string[] extensions)
{
    var allowedExtensions = new HashSet<string>(extensions, StringComparer.OrdinalIgnoreCase);

    return dirInfo.EnumerateFiles()
                  .Where(f => allowedExtensions.Contains(f.Extension));
}

이것은 여기의 다른 모든 답변보다 (약간) 빠릅니다.
NET 3.5에서 교체 EnumerateFiles하여 GetFiles(느린 속도이다).

다음과 같이 사용하십시오.

var files = new DirectoryInfo(...).GetFilesByExtensions(".jpg", ".mov", ".gif", ".mp4");

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GetFiles단일 검색 패턴 만 허용 하므로 그렇게 할 수 없습니다 . 대신 GetFiles패턴없이 호출 하고 코드에서 결과를 필터링 할 수 있습니다.

string[] extensions = new[] { ".jpg", ".tiff", ".bmp" };

FileInfo[] files =
    dinfo.GetFiles()
         .Where(f => extensions.Contains(f.Extension.ToLower()))
         .ToArray();

.NET 4로 작업하는 경우 EnumerateFiles메서드를 사용하여 모든 FileInfo 개체를 한 번에 메모리에로드하지 않도록 할 수 있습니다 .

string[] extensions = new[] { ".jpg", ".tiff", ".bmp" };

FileInfo[] files =
    dinfo.EnumerateFiles()
         .Where(f => extensions.Contains(f.Extension.ToLower()))
         .ToArray();

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You can use LINQ Union method:

dir.GetFiles("*.txt").Union(dir.GetFiles("*.jpg")).ToArray();

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The following retrieves the jpg, tiff and bmp files and gives you an IEnumerable<FileInfo> over which you can iterate:

var files = dinfo.GetFiles("*.jpg")
    .Concat(dinfo.GetFiles("*.tiff"))
    .Concat(dinfo.GetFiles("*.bmp"));

If you really need an array, simply stick .ToArray() at the end of this.

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I'm not sure if that is possible. The MSDN GetFiles reference says a search pattern, not a list of search patterns.

I might be inclined to fetch each list separately and "foreach" them into a final list.

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I know there is a more elegant way to do this and I'm open to suggestions... this is what I did:

          try
            {


             // Set directory for list to be made of
                DirectoryInfo jpegInfo = new DirectoryInfo(destinationFolder);
                DirectoryInfo jpgInfo = new DirectoryInfo(destinationFolder);
                DirectoryInfo gifInfo = new DirectoryInfo(destinationFolder);
                DirectoryInfo tiffInfo = new DirectoryInfo(destinationFolder);
                DirectoryInfo bmpInfo = new DirectoryInfo(destinationFolder);

                // Set file type
                FileInfo[] Jpegs = jpegInfo.GetFiles("*.jpeg");
                FileInfo[] Jpgs = jpegInfo.GetFiles("*.jpg");
                FileInfo[] Gifs = gifInfo.GetFiles("*.gif");
                FileInfo[] Tiffs = gifInfo.GetFiles("*.tiff");
                FileInfo[] Bmps = gifInfo.GetFiles("*.bmp");

        //  listBox1.Items.Add(@"");  // Hack for the first list item no preview problem
        // Iterate through each file, displaying only the name inside the listbox...
        foreach (FileInfo file in Jpegs)
        {
                listBox1.Items.Add(file.Name);
                Photo curPhoto = new Photo();
                curPhoto.PhotoLocation = file.FullName;
                metaData.AddPhoto(curPhoto);
            }

          foreach (FileInfo file in Jpgs)
          {
              listBox1.Items.Add(file.Name);
                Photo curPhoto = new Photo();
                curPhoto.PhotoLocation = file.FullName;
                metaData.AddPhoto(curPhoto);
            }
          foreach (FileInfo file in Gifs)
          {
              listBox1.Items.Add(file.Name);
              Photo curPhoto = new Photo();
              curPhoto.PhotoLocation = file.FullName;
              metaData.AddPhoto(curPhoto);
          }
          foreach (FileInfo file in Tiffs)
          {
              listBox1.Items.Add(file.Name);
              Photo curPhoto = new Photo();
              curPhoto.PhotoLocation = file.FullName;
              metaData.AddPhoto(curPhoto);
          }
          foreach (FileInfo file in Bmps)
          {
              listBox1.Items.Add(file.Name);
              Photo curPhoto = new Photo();
              curPhoto.PhotoLocation = file.FullName;
              metaData.AddPhoto(curPhoto);
          }

참고URL : https://stackoverflow.com/questions/3527203/getfiles-with-multiple-extensions