SQL Server 2005의 날짜 / 시간에서 월 및 연도 가져 오기

SQL Server 2005의 날짜 / 시간에서 월 및 연도 가져 오기

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'Jan 2008'과 같은 SQL Server의 datetime에서 월 + 연도가 필요합니다. 월, 연도별로 쿼리를 그룹화하고 있습니다. 나는 datepart, convert 등과 같은 기능을 검색하고 찾았지만 그중 어느 것도 이것에 유용하지 않은 것 같습니다. 여기서 뭔가 빠졌나요? 이것에 대한 기능이 있습니까?

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해당 형식의 문자열로 되돌리려면;

SELECT 
  CONVERT(CHAR(4), date_of_birth, 100) + CONVERT(CHAR(4), date_of_birth, 120) 
FROM customers

다른 형식 옵션은 다음과 같습니다.

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select 
datepart(month,getdate()) -- integer (1,2,3...)
,datepart(year,getdate()) -- integer
,datename(month,getdate()) -- string ('September',...)

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SQL Server 2012부터 다음을 사용할 수 있습니다.

SELECT FORMAT(@date, 'yyyyMM')

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사용하다:

select datepart(mm,getdate())  --to get month value
select datename(mm,getdate())  --to get name of month

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재미있게도 저는 SQL Server와 LINQ에서 동일한 쿼리를 작성하고있었습니다.

SELECT 
    DATENAME(mm, article.Created) AS Month, 
    DATENAME(yyyy, article.Created) AS Year, 
    COUNT(*) AS Total 
FROM Articles AS article 
GROUP BY 
    DATENAME(mm, article.Created), 
    DATENAME(yyyy, article.Created) 
ORDER BY Month, Year DESC

다음 출력 (예제)을 생성합니다.

Month | Year | Total

January | 2009 | 2

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SQL Server 2012에서는 아래를 사용할 수 있습니다.

FORMAT (getdate (), 'MMM yyyy') 선택

정확한 "2016 년 6 월"을 제공합니다.

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이건 어때요?

Select DateName( Month, getDate() ) + ' ' + DateName( Year, getDate() )

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( Month(Created) + ',' + Year(Created) ) AS Date

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그 형식은 존재하지 않습니다. 두 가지를 조합해야합니다.

select convert(varchar(4),getdate(),100)  + convert(varchar(4),year(getdate()))

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이를 수행하는 가장 좋은 방법은 다음과 같습니다.

dateadd(month,datediff(month,0,*your_date*),0)

it will keep your datetime type

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returns the full month name, -, full year e.g. March-2017

CONCAT(DATENAME(mm, GetDate()), '-', DATEPART(yy, GetDate()))

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I had the same problem and after looking around I found this:

SELECT DATENAME(yyyy, date) AS year
FROM Income
GROUP BY DATENAME(yyyy, date)

It's working great!

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Converting the date to the first of the month allows you to Group By and Order By a single attribute, and it's faster in my experience.

declare @mytable table(mydate datetime)
declare @date datetime
set @date = '19000101'
while @date < getdate() begin
    insert into @mytable values(@date)
    set @date = dateadd(day,1,@date)
end

select count(*) total_records from @mytable

select dateadd(month,datediff(month,0,mydate),0) first_of_the_month, count(*) cnt
from @mytable
group by dateadd(month,datediff(month,0,mydate),0)

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---Lalmuni Demos---
create table Users
(
userid int,date_of_birth date
)
---insert values---
insert into Users values(4,'9/10/1991')

select DATEDIFF(year,date_of_birth, getdate()) - (CASE WHEN (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()),date_of_birth)) > getdate() THEN 1 ELSE 0 END) as Years, 
MONTH(getdate() - (DATEADD(year, DATEDIFF(year, date_of_birth, getdate()), date_of_birth))) - 1 as Months, 
DAY(getdate() - (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()), date_of_birth))) - 1 as Days,
from users

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cast(cast(sq.QuotaDate as date) as varchar(7))

gives "2006-04" format

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The question is about SQL Server 2005, many of the answers here are for later version SQL Server.

select convert (varchar(7), getdate(),20)
--Typical output 2015-04

SQL Server 2005 does not have date function which was introduced in SQL Server 2008

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Yes, you can use datename(month,intime) to get the month in text.

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  ,datename(month,(od.SHIP_DATE)) as MONTH_

Answer: MONTH_ January January September October December October September

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It's work great.

DECLARE @pYear VARCHAR(4)

DECLARE @pMonth VARCHAR(2)

DECLARE @pDay VARCHAR(2)

SET @pYear  = RIGHT(CONVERT(CHAR(10), GETDATE(), 101), 4)

SET @pMonth = LEFT(CONVERT(CHAR(10), GETDATE(), 101), 2)

SET @pDay   = SUBSTRING(CONVERT(CHAR(10), GETDATE(), 101), 4,2)

SELECT @pYear,@pMonth,@pDay

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The following works perfectly! I just used it, try it out.

date_format(date,'%Y-%c')

참고URL : https://stackoverflow.com/questions/45535/get-month-and-year-from-a-datetime-in-sql-server-2005