SQL에서 테이블 크기를 찾는 방법은 무엇입니까?
SQL에서 테이블 크기를 찾는 방법은 무엇입니까?
SQL 서버 :-
sp_spaceused 'TableName'
또는 관리 스튜디오에서 : 테이블-> 속성-> 스토리지를 마우스 오른쪽 버튼으로 클릭합니다.
MySQL :-
SELECT table_schema, table_name, data_length, index_length FROM information_schema.tables
Sybase :-
sp_spaceused 'TableName'
오라클 :-오라클 내 에서 테이블 크기를 계산하는 방법
ratty와 Haim의 게시물 (댓글 포함)의 답변을 결합하여 SQL Server의 경우 지금까지 가장 우아한 것 같습니다.
-- DROP TABLE #tmpTableSizes
CREATE TABLE #tmpTableSizes
(
tableName varchar(100),
numberofRows varchar(100),
reservedSize varchar(50),
dataSize varchar(50),
indexSize varchar(50),
unusedSize varchar(50)
)
insert #tmpTableSizes
EXEC sp_MSforeachtable @command1="EXEC sp_spaceused '?'"
select * from #tmpTableSizes
order by cast(LEFT(reservedSize, LEN(reservedSize) - 4) as int) desc
이렇게하면 예약 된 크기 순으로 모든 테이블 목록이 가장 큰 것에서 가장 작은 것 순으로 제공됩니다.
사용자 지정 이름 테이블 크기 (GB)를 찾기 위한 쿼리 ( https://stackoverflow.com/a/7892349/1737819 수정 ). 이것을 시도하고 'YourTableName'을 테이블 이름으로 바꾸십시오.
SELECT
t.NAME AS TableName,
p.rows AS RowCounts,
CONVERT(DECIMAL,SUM(a.total_pages)) * 8 / 1024 / 1024 AS TotalSpaceGB,
SUM(a.used_pages) * 8 / 1024 / 1024 AS UsedSpaceGB ,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 / 1024 / 1024 AS UnusedSpaceGB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME = 'YourTable'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
UsedSpaceGB DESC, t.Name
SQL Server는 인덱스 크기를 포함하여 테이블 크기를 쉽게 표시하기 위해 실행할 수있는 기본 제공 저장 프로 시저를 제공합니다.
sp_spaceused ‘Tablename’
SQL Server provides a built-in stored procedure that you can run to easily show the size of a table, including the size of the indexes… which might surprise you.
Syntax:
sp_spaceused ‘Tablename’
see in :
http://www.howtogeek.com/howto/database/determine-size-of-a-table-in-sql-server/
Do you by size mean the number of records in the table, by any chance? In that case:
SELECT COUNT(*) FROM your_table_name
I know that in SQL 2012 (may work in other versions) you can do the following:
- Right click on the database name in the Object Explorer.
- Select Reports > Standard Reports > Disk Usage by Top Tables.
That will give you a list of the top 1000 tables and then you can order it by data size etc.
And in PostgreSQL:
SELECT pg_size_pretty(pg_relation_size('tablename'));
Here's a simple query, if you are just trying to find the largest tables.
-- Find largest table partitions
SELECT top 20 obj.name, LTRIM (STR ( sz.in_row_data_page_count * 8, 15, 0) + ' KB') as Size, * FROM sys.dm_db_partition_stats sz
inner join sys.objects obj on obj.object_id = sz.object_id
order by sz.in_row_data_page_count desc
SQL Server, nicely formatted table for all tables in KB/MB:
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
t.Name
You may refer the answer by Marc_s in another thread, Very useful.
Get size of all tables in database
참고URL : https://stackoverflow.com/questions/3606366/how-to-find-the-size-of-a-table-in-sql
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